♨️Specific Heat Capacity
Converter IT BTU per Pound Mass Degree Fahrenheit em Joule per Kilogram Kelvin
Conversor online de IT BTUs per Pound Mass Degree Fahrenheit para Joules per Kilogram Kelvin (Btu_IT/(lbm·°F) para J/(kg·K)) com fórmula detalhada e tabela de conversão.
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Specific Heat Capacity8 unidades
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How the Calculation Works (Linear Scaling)
Formula:
Joule per Kilogram Kelvin = IT BTU per Pound Mass Degree Fahrenheit × 4186.8
Substitution:1 × 4186.8
Calculated Result:4186.8 J/(kg·K)
Since 1 IT BTU per Pound Mass Degree Fahrenheit = 4186.8 Joules per Kilogram Kelvin, multiply the value in IT BTUs per Pound Mass Degree Fahrenheit by 4186.8.
Standard Ratio Factor:1 Btu_IT/(lbm·°F) = 4186.8 J/(kg·K)
IT BTU per Pound Mass Degree Fahrenheit to Joule per Kilogram Kelvin Conversion Table
Precomputed values for quick reference and printing.
IT BTU per Pound Mass Degree Fahrenheit → Joule per Kilogram Kelvin(Btu_IT/(lbm·°F) → J/(kg·K))
| IT BTU per Pound Mass Degree Fahrenheit | Joule per Kilogram Kelvin |
|---|---|
| 1 Btu_IT/(lbm·°F) | 4186.8 J/(kg·K) |
| 2 Btu_IT/(lbm·°F) | 8373.6 J/(kg·K) |
| 3 Btu_IT/(lbm·°F) | 12560.4 J/(kg·K) |
| 4 Btu_IT/(lbm·°F) | 16747.2 J/(kg·K) |
| 5 Btu_IT/(lbm·°F) | 20934 J/(kg·K) |
| 6 Btu_IT/(lbm·°F) | 25120.8 J/(kg·K) |
| 7 Btu_IT/(lbm·°F) | 29307.6 J/(kg·K) |
| 8 Btu_IT/(lbm·°F) | 33494.4 J/(kg·K) |
| 9 Btu_IT/(lbm·°F) | 37681.2 J/(kg·K) |
| 10 Btu_IT/(lbm·°F) | 41868 J/(kg·K) |
| 15 Btu_IT/(lbm·°F) | 62802 J/(kg·K) |
| 20 Btu_IT/(lbm·°F) | 83736 J/(kg·K) |
| 25 Btu_IT/(lbm·°F) | 104670 J/(kg·K) |
| 30 Btu_IT/(lbm·°F) | 125604 J/(kg·K) |
| 40 Btu_IT/(lbm·°F) | 167472 J/(kg·K) |
| 50 Btu_IT/(lbm·°F) | 209340 J/(kg·K) |
| 75 Btu_IT/(lbm·°F) | 314010 J/(kg·K) |
| 100 Btu_IT/(lbm·°F) | 418680 J/(kg·K) |
Joule per Kilogram Kelvin → IT BTU per Pound Mass Degree Fahrenheit(J/(kg·K) → Btu_IT/(lbm·°F))
| Joule per Kilogram Kelvin | IT BTU per Pound Mass Degree Fahrenheit |
|---|---|
| 1 J/(kg·K) | 0.0002388459 Btu_IT/(lbm·°F) |
| 2 J/(kg·K) | 0.0004776918 Btu_IT/(lbm·°F) |
| 3 J/(kg·K) | 0.0007165377 Btu_IT/(lbm·°F) |
| 4 J/(kg·K) | 0.0009553836 Btu_IT/(lbm·°F) |
| 5 J/(kg·K) | 0.0011942295 Btu_IT/(lbm·°F) |
| 6 J/(kg·K) | 0.0014330754 Btu_IT/(lbm·°F) |
| 7 J/(kg·K) | 0.0016719213 Btu_IT/(lbm·°F) |
| 8 J/(kg·K) | 0.0019107672 Btu_IT/(lbm·°F) |
| 9 J/(kg·K) | 0.0021496131 Btu_IT/(lbm·°F) |
| 10 J/(kg·K) | 0.002388459 Btu_IT/(lbm·°F) |
| 15 J/(kg·K) | 0.0035826884 Btu_IT/(lbm·°F) |
| 20 J/(kg·K) | 0.0047769179 Btu_IT/(lbm·°F) |
| 25 J/(kg·K) | 0.0059711474 Btu_IT/(lbm·°F) |
| 30 J/(kg·K) | 0.0071653769 Btu_IT/(lbm·°F) |
| 40 J/(kg·K) | 0.0095538359 Btu_IT/(lbm·°F) |
| 50 J/(kg·K) | 0.011942295 Btu_IT/(lbm·°F) |
| 75 J/(kg·K) | 0.017913442 Btu_IT/(lbm·°F) |
| 100 J/(kg·K) | 0.02388459 Btu_IT/(lbm·°F) |
IT BTU per Pound Mass Degree Fahrenheit (Btu_IT/(lbm·°F))
The US customary specific heat capacity unit, defined as 1 IT BTU per pound-mass per °F interval. It is numerically equal to exactly 4,186.8 J/(kg·K).
Joule per Kilogram Kelvin (J/(kg·K))
The SI unit of specific heat capacity (c), representing the heat energy in joules required to raise 1 kilogram of a substance by 1 kelvin.
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Related Conversion Calculators
Joule per Kilogram Kelvin to IT BTU per Pound Mass Degree Fahrenheit→Kilojoule per Kilogram Kelvin to Joule per Kilogram Kelvin→IT Calorie per Gram Degree Celsius to Joule per Kilogram Kelvin→Thermochemical Calorie per Gram Degree Celsius to Joule per Kilogram Kelvin→Joule per Kilogram Kelvin to Kilojoule per Kilogram Kelvin→