Convert Joule per Kilogram Kelvin to IT BTU per Pound Mass Degree Fahrenheit
Live bidirectional calculator for Joules per Kilogram Kelvin (J/(kg·K)) and IT BTUs per Pound Mass Degree Fahrenheit (Btu_IT/(lbm·°F)) with verified formula and conversion charts.
Specific Heat Capacity8 units
How the Calculation Works (Linear Scaling)
Since 1 IT BTU per Pound Mass Degree Fahrenheit = 4186.8 Joules per Kilogram Kelvin, divide the value in Joules per Kilogram Kelvin by 4186.8.
Joule per Kilogram Kelvin to IT BTU per Pound Mass Degree Fahrenheit Conversion Table
Precomputed values for quick reference and printing.
| Joule per Kilogram Kelvin | IT BTU per Pound Mass Degree Fahrenheit |
|---|---|
| 1 J/(kg·K) | 0.0002 Btu_IT/(lbm·°F) |
| 2 J/(kg·K) | 0.0005 Btu_IT/(lbm·°F) |
| 3 J/(kg·K) | 0.0007 Btu_IT/(lbm·°F) |
| 4 J/(kg·K) | 0.001 Btu_IT/(lbm·°F) |
| 5 J/(kg·K) | 0.0012 Btu_IT/(lbm·°F) |
| 6 J/(kg·K) | 0.0014 Btu_IT/(lbm·°F) |
| 7 J/(kg·K) | 0.0017 Btu_IT/(lbm·°F) |
| 8 J/(kg·K) | 0.0019 Btu_IT/(lbm·°F) |
| 9 J/(kg·K) | 0.0021 Btu_IT/(lbm·°F) |
| 10 J/(kg·K) | 0.0024 Btu_IT/(lbm·°F) |
| 15 J/(kg·K) | 0.0036 Btu_IT/(lbm·°F) |
| 20 J/(kg·K) | 0.0048 Btu_IT/(lbm·°F) |
| 25 J/(kg·K) | 0.006 Btu_IT/(lbm·°F) |
| 30 J/(kg·K) | 0.0072 Btu_IT/(lbm·°F) |
| 40 J/(kg·K) | 0.0096 Btu_IT/(lbm·°F) |
| 50 J/(kg·K) | 0.0119 Btu_IT/(lbm·°F) |
| 75 J/(kg·K) | 0.0179 Btu_IT/(lbm·°F) |
| 100 J/(kg·K) | 0.0239 Btu_IT/(lbm·°F) |
| IT BTU per Pound Mass Degree Fahrenheit | Joule per Kilogram Kelvin |
|---|---|
| 1 Btu_IT/(lbm·°F) | 4186.8 J/(kg·K) |
| 2 Btu_IT/(lbm·°F) | 8373.6 J/(kg·K) |
| 3 Btu_IT/(lbm·°F) | 12560.4 J/(kg·K) |
| 4 Btu_IT/(lbm·°F) | 16747.2 J/(kg·K) |
| 5 Btu_IT/(lbm·°F) | 20934 J/(kg·K) |
| 6 Btu_IT/(lbm·°F) | 25120.8 J/(kg·K) |
| 7 Btu_IT/(lbm·°F) | 29307.6 J/(kg·K) |
| 8 Btu_IT/(lbm·°F) | 33494.4 J/(kg·K) |
| 9 Btu_IT/(lbm·°F) | 37681.2 J/(kg·K) |
| 10 Btu_IT/(lbm·°F) | 41868 J/(kg·K) |
| 15 Btu_IT/(lbm·°F) | 62802 J/(kg·K) |
| 20 Btu_IT/(lbm·°F) | 83736 J/(kg·K) |
| 25 Btu_IT/(lbm·°F) | 104670 J/(kg·K) |
| 30 Btu_IT/(lbm·°F) | 125604 J/(kg·K) |
| 40 Btu_IT/(lbm·°F) | 167472 J/(kg·K) |
| 50 Btu_IT/(lbm·°F) | 209340 J/(kg·K) |
| 75 Btu_IT/(lbm·°F) | 314010 J/(kg·K) |
| 100 Btu_IT/(lbm·°F) | 418680 J/(kg·K) |
About Joule per Kilogram Kelvin (J/(kg·K))
The SI unit of specific heat capacity (c), representing the heat energy in joules required to raise 1 kilogram of a substance by 1 kelvin.
History: Codified as the SI standard following the development of modern thermodynamics (liquid water has c ≈ 4184 J/(kg·K)).
Common Uses: Calorimetry, thermodynamic process design, thermal mass engineering.
About IT BTU per Pound Mass Degree Fahrenheit (Btu_IT/(lbm·°F))
The US customary specific heat capacity unit, defined as 1 IT BTU per pound-mass per °F interval. It is numerically equal to exactly 4,186.8 J/(kg·K).
History: Engineered so liquid water near room temperature has a specific heat of approximately 1.0 Btu/(lbm·°F).
Common Uses: US HVAC calculations, ASHRAE heat load sizing, American boiler engineering.
❓ Frequently Asked Questions
How many IT BTUs per Pound Mass Degree Fahrenheit are in 1 Joule per Kilogram Kelvin?
There are exactly 0.000239 IT BTUs per Pound Mass Degree Fahrenheit in 1 Joule per Kilogram Kelvin (1 J/(kg·K) = 0.000239 Btu_IT/(lbm·°F)).
What is the formula to convert Joule per Kilogram Kelvin to IT BTU per Pound Mass Degree Fahrenheit?
The formula is: IT BTU per Pound Mass Degree Fahrenheit = Joule per Kilogram Kelvin / 4186.8. Since 1 IT BTU per Pound Mass Degree Fahrenheit = 4186.8 Joules per Kilogram Kelvin, divide the value in Joules per Kilogram Kelvin by 4186.8.
How do I convert 1 J/(kg·K) to Btu_IT/(lbm·°F) manually?
To convert 1 J/(kg·K) to Btu_IT/(lbm·°F): apply the formula IT BTU per Pound Mass Degree Fahrenheit = Joule per Kilogram Kelvin / 4186.8. Substituting gives: 1 / 4186.8 = 0.0002 Btu_IT/(lbm·°F).