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♨️Specific Heat Capacity Converter

Convert IT BTU per Pound Mass Degree Fahrenheit to Joule per Kilogram Kelvin

Live bidirectional calculator for IT BTUs per Pound Mass Degree Fahrenheit (Btu_IT/(lbm·°F)) and Joules per Kilogram Kelvin (J/(kg·K)) with verified formula and conversion charts.

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Specific Heat Capacity8 units

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How the Calculation Works (Linear Scaling)

Formula:
Joule per Kilogram Kelvin = IT BTU per Pound Mass Degree Fahrenheit × 4186.8
Substitution:1 × 4186.8
Calculated Result:4186.8 J/(kg·K)

Since 1 IT BTU per Pound Mass Degree Fahrenheit = 4186.8 Joules per Kilogram Kelvin, multiply the value in IT BTUs per Pound Mass Degree Fahrenheit by 4186.8.

Standard Ratio Factor:1 Btu_IT/(lbm·°F) = 4186.8 J/(kg·K)

IT BTU per Pound Mass Degree Fahrenheit to Joule per Kilogram Kelvin Conversion Table

Precomputed values for quick reference and printing.

IT BTU per Pound Mass Degree Fahrenheit → Joule per Kilogram Kelvin(Btu_IT/(lbm·°F) → J/(kg·K))
IT BTU per Pound Mass Degree FahrenheitJoule per Kilogram Kelvin
1 Btu_IT/(lbm·°F)4186.8 J/(kg·K)
2 Btu_IT/(lbm·°F)8373.6 J/(kg·K)
3 Btu_IT/(lbm·°F)12560.4 J/(kg·K)
4 Btu_IT/(lbm·°F)16747.2 J/(kg·K)
5 Btu_IT/(lbm·°F)20934 J/(kg·K)
6 Btu_IT/(lbm·°F)25120.8 J/(kg·K)
7 Btu_IT/(lbm·°F)29307.6 J/(kg·K)
8 Btu_IT/(lbm·°F)33494.4 J/(kg·K)
9 Btu_IT/(lbm·°F)37681.2 J/(kg·K)
10 Btu_IT/(lbm·°F)41868 J/(kg·K)
15 Btu_IT/(lbm·°F)62802 J/(kg·K)
20 Btu_IT/(lbm·°F)83736 J/(kg·K)
25 Btu_IT/(lbm·°F)104670 J/(kg·K)
30 Btu_IT/(lbm·°F)125604 J/(kg·K)
40 Btu_IT/(lbm·°F)167472 J/(kg·K)
50 Btu_IT/(lbm·°F)209340 J/(kg·K)
75 Btu_IT/(lbm·°F)314010 J/(kg·K)
100 Btu_IT/(lbm·°F)418680 J/(kg·K)
Joule per Kilogram Kelvin → IT BTU per Pound Mass Degree Fahrenheit(J/(kg·K) → Btu_IT/(lbm·°F))
Joule per Kilogram KelvinIT BTU per Pound Mass Degree Fahrenheit
1 J/(kg·K)0.0002 Btu_IT/(lbm·°F)
2 J/(kg·K)0.0005 Btu_IT/(lbm·°F)
3 J/(kg·K)0.0007 Btu_IT/(lbm·°F)
4 J/(kg·K)0.001 Btu_IT/(lbm·°F)
5 J/(kg·K)0.0012 Btu_IT/(lbm·°F)
6 J/(kg·K)0.0014 Btu_IT/(lbm·°F)
7 J/(kg·K)0.0017 Btu_IT/(lbm·°F)
8 J/(kg·K)0.0019 Btu_IT/(lbm·°F)
9 J/(kg·K)0.0021 Btu_IT/(lbm·°F)
10 J/(kg·K)0.0024 Btu_IT/(lbm·°F)
15 J/(kg·K)0.0036 Btu_IT/(lbm·°F)
20 J/(kg·K)0.0048 Btu_IT/(lbm·°F)
25 J/(kg·K)0.006 Btu_IT/(lbm·°F)
30 J/(kg·K)0.0072 Btu_IT/(lbm·°F)
40 J/(kg·K)0.0096 Btu_IT/(lbm·°F)
50 J/(kg·K)0.0119 Btu_IT/(lbm·°F)
75 J/(kg·K)0.0179 Btu_IT/(lbm·°F)
100 J/(kg·K)0.0239 Btu_IT/(lbm·°F)

About IT BTU per Pound Mass Degree Fahrenheit (Btu_IT/(lbm·°F))

The US customary specific heat capacity unit, defined as 1 IT BTU per pound-mass per °F interval. It is numerically equal to exactly 4,186.8 J/(kg·K).

History: Engineered so liquid water near room temperature has a specific heat of approximately 1.0 Btu/(lbm·°F).

Common Uses: US HVAC calculations, ASHRAE heat load sizing, American boiler engineering.

About Joule per Kilogram Kelvin (J/(kg·K))

The SI unit of specific heat capacity (c), representing the heat energy in joules required to raise 1 kilogram of a substance by 1 kelvin.

History: Codified as the SI standard following the development of modern thermodynamics (liquid water has c ≈ 4184 J/(kg·K)).

Common Uses: Calorimetry, thermodynamic process design, thermal mass engineering.

❓ Frequently Asked Questions

How many Joules per Kilogram Kelvin are in 1 IT BTU per Pound Mass Degree Fahrenheit?

There are exactly 4186.8 Joules per Kilogram Kelvin in 1 IT BTU per Pound Mass Degree Fahrenheit (1 Btu_IT/(lbm·°F) = 4186.8 J/(kg·K)).

What is the formula to convert IT BTU per Pound Mass Degree Fahrenheit to Joule per Kilogram Kelvin?

The formula is: Joule per Kilogram Kelvin = IT BTU per Pound Mass Degree Fahrenheit × 4186.8. Since 1 IT BTU per Pound Mass Degree Fahrenheit = 4186.8 Joules per Kilogram Kelvin, multiply the value in IT BTUs per Pound Mass Degree Fahrenheit by 4186.8.

How do I convert 1 Btu_IT/(lbm·°F) to J/(kg·K) manually?

To convert 1 Btu_IT/(lbm·°F) to J/(kg·K): apply the formula Joule per Kilogram Kelvin = IT BTU per Pound Mass Degree Fahrenheit × 4186.8. Substituting gives: 1 × 4186.8 = 4186.8 J/(kg·K).