Convert IT Calorie per Gram Degree Celsius to Joule per Kilogram Kelvin
Live bidirectional calculator for IT Calories per Gram Degree Celsius (cal_IT/(g·°C)) and Joules per Kilogram Kelvin (J/(kg·K)) with verified formula and conversion charts.
Specific Heat Capacity8 units
How the Calculation Works (Linear Scaling)
Since 1 IT Calorie per Gram Degree Celsius = 4186.8 Joules per Kilogram Kelvin, multiply the value in IT Calories per Gram Degree Celsius by 4186.8.
IT Calorie per Gram Degree Celsius to Joule per Kilogram Kelvin Conversion Table
Precomputed values for quick reference and printing.
| IT Calorie per Gram Degree Celsius | Joule per Kilogram Kelvin |
|---|---|
| 1 cal_IT/(g·°C) | 4186.8 J/(kg·K) |
| 2 cal_IT/(g·°C) | 8373.6 J/(kg·K) |
| 3 cal_IT/(g·°C) | 12560.4 J/(kg·K) |
| 4 cal_IT/(g·°C) | 16747.2 J/(kg·K) |
| 5 cal_IT/(g·°C) | 20934 J/(kg·K) |
| 6 cal_IT/(g·°C) | 25120.8 J/(kg·K) |
| 7 cal_IT/(g·°C) | 29307.6 J/(kg·K) |
| 8 cal_IT/(g·°C) | 33494.4 J/(kg·K) |
| 9 cal_IT/(g·°C) | 37681.2 J/(kg·K) |
| 10 cal_IT/(g·°C) | 41868 J/(kg·K) |
| 15 cal_IT/(g·°C) | 62802 J/(kg·K) |
| 20 cal_IT/(g·°C) | 83736 J/(kg·K) |
| 25 cal_IT/(g·°C) | 104670 J/(kg·K) |
| 30 cal_IT/(g·°C) | 125604 J/(kg·K) |
| 40 cal_IT/(g·°C) | 167472 J/(kg·K) |
| 50 cal_IT/(g·°C) | 209340 J/(kg·K) |
| 75 cal_IT/(g·°C) | 314010 J/(kg·K) |
| 100 cal_IT/(g·°C) | 418680 J/(kg·K) |
| Joule per Kilogram Kelvin | IT Calorie per Gram Degree Celsius |
|---|---|
| 1 J/(kg·K) | 0.0002 cal_IT/(g·°C) |
| 2 J/(kg·K) | 0.0005 cal_IT/(g·°C) |
| 3 J/(kg·K) | 0.0007 cal_IT/(g·°C) |
| 4 J/(kg·K) | 0.001 cal_IT/(g·°C) |
| 5 J/(kg·K) | 0.0012 cal_IT/(g·°C) |
| 6 J/(kg·K) | 0.0014 cal_IT/(g·°C) |
| 7 J/(kg·K) | 0.0017 cal_IT/(g·°C) |
| 8 J/(kg·K) | 0.0019 cal_IT/(g·°C) |
| 9 J/(kg·K) | 0.0021 cal_IT/(g·°C) |
| 10 J/(kg·K) | 0.0024 cal_IT/(g·°C) |
| 15 J/(kg·K) | 0.0036 cal_IT/(g·°C) |
| 20 J/(kg·K) | 0.0048 cal_IT/(g·°C) |
| 25 J/(kg·K) | 0.006 cal_IT/(g·°C) |
| 30 J/(kg·K) | 0.0072 cal_IT/(g·°C) |
| 40 J/(kg·K) | 0.0096 cal_IT/(g·°C) |
| 50 J/(kg·K) | 0.0119 cal_IT/(g·°C) |
| 75 J/(kg·K) | 0.0179 cal_IT/(g·°C) |
| 100 J/(kg·K) | 0.0239 cal_IT/(g·°C) |
📌 Standard Benchmark Reference Values
International Steam Table calorie definition standard.
Exact RatioAbout IT Calorie per Gram Degree Celsius (cal_IT/(g·°C))
Specific heat capacity equal to 4,186.8 J/(kg·K), derived from 1 International Table calorie (4.1868 J) per gram (0.001 kg).
History: Standardized at the 1929 International Steam Table Conference.
Common Uses: Steam engineering literature, historical thermodynamic properties of fluids.
About Joule per Kilogram Kelvin (J/(kg·K))
The SI unit of specific heat capacity (c), representing the heat energy in joules required to raise 1 kilogram of a substance by 1 kelvin.
History: Codified as the SI standard following the development of modern thermodynamics (liquid water has c ≈ 4184 J/(kg·K)).
Common Uses: Calorimetry, thermodynamic process design, thermal mass engineering.
❓ Frequently Asked Questions
How many Joules per Kilogram Kelvin are in 1 IT Calorie per Gram Degree Celsius?
There are exactly 4186.8 Joules per Kilogram Kelvin in 1 IT Calorie per Gram Degree Celsius (1 cal_IT/(g·°C) = 4186.8 J/(kg·K)).
What is the formula to convert IT Calorie per Gram Degree Celsius to Joule per Kilogram Kelvin?
The formula is: Joule per Kilogram Kelvin = IT Calorie per Gram Degree Celsius × 4186.8. Since 1 IT Calorie per Gram Degree Celsius = 4186.8 Joules per Kilogram Kelvin, multiply the value in IT Calories per Gram Degree Celsius by 4186.8.
How do I convert 1 cal_IT/(g·°C) to J/(kg·K) manually?
To convert 1 cal_IT/(g·°C) to J/(kg·K): apply the formula Joule per Kilogram Kelvin = IT Calorie per Gram Degree Celsius × 4186.8. Substituting gives: 1 × 4186.8 = 4186.8 J/(kg·K).