♨️Specific Heat Capacity
Convertir Joule per Kilogram Kelvin en IT BTU per Pound Mass Degree Fahrenheit
Convertissez facilement les Joules per Kilogram Kelvin en IT BTUs per Pound Mass Degree Fahrenheit (J/(kg·K) en Btu_IT/(lbm·°F)) avec formule détaillée et tableau de conversion.
♨️
Specific Heat Capacity8 unités
⚠️
💡
How the Calculation Works (Linear Scaling)
Formula:
IT BTU per Pound Mass Degree Fahrenheit = Joule per Kilogram Kelvin / 4186.8
Substitution:1 / 4186.8
Calculated Result:0.0002 Btu_IT/(lbm·°F)
Since 1 IT BTU per Pound Mass Degree Fahrenheit = 4186.8 Joules per Kilogram Kelvin, divide the value in Joules per Kilogram Kelvin by 4186.8.
Standard Ratio Factor:1 J/(kg·K) = 0.000239 Btu_IT/(lbm·°F)
Joule per Kilogram Kelvin to IT BTU per Pound Mass Degree Fahrenheit Conversion Table
Precomputed values for quick reference and printing.
Joule per Kilogram Kelvin → IT BTU per Pound Mass Degree Fahrenheit(J/(kg·K) → Btu_IT/(lbm·°F))
| Joule per Kilogram Kelvin | IT BTU per Pound Mass Degree Fahrenheit |
|---|---|
| 1 J/(kg·K) | 0.0002388459 Btu_IT/(lbm·°F) |
| 2 J/(kg·K) | 0.0004776918 Btu_IT/(lbm·°F) |
| 3 J/(kg·K) | 0.0007165377 Btu_IT/(lbm·°F) |
| 4 J/(kg·K) | 0.0009553836 Btu_IT/(lbm·°F) |
| 5 J/(kg·K) | 0.0011942295 Btu_IT/(lbm·°F) |
| 6 J/(kg·K) | 0.0014330754 Btu_IT/(lbm·°F) |
| 7 J/(kg·K) | 0.0016719213 Btu_IT/(lbm·°F) |
| 8 J/(kg·K) | 0.0019107672 Btu_IT/(lbm·°F) |
| 9 J/(kg·K) | 0.0021496131 Btu_IT/(lbm·°F) |
| 10 J/(kg·K) | 0.002388459 Btu_IT/(lbm·°F) |
| 15 J/(kg·K) | 0.0035826884 Btu_IT/(lbm·°F) |
| 20 J/(kg·K) | 0.0047769179 Btu_IT/(lbm·°F) |
| 25 J/(kg·K) | 0.0059711474 Btu_IT/(lbm·°F) |
| 30 J/(kg·K) | 0.0071653769 Btu_IT/(lbm·°F) |
| 40 J/(kg·K) | 0.0095538359 Btu_IT/(lbm·°F) |
| 50 J/(kg·K) | 0.011942295 Btu_IT/(lbm·°F) |
| 75 J/(kg·K) | 0.017913442 Btu_IT/(lbm·°F) |
| 100 J/(kg·K) | 0.02388459 Btu_IT/(lbm·°F) |
IT BTU per Pound Mass Degree Fahrenheit → Joule per Kilogram Kelvin(Btu_IT/(lbm·°F) → J/(kg·K))
| IT BTU per Pound Mass Degree Fahrenheit | Joule per Kilogram Kelvin |
|---|---|
| 1 Btu_IT/(lbm·°F) | 4186.8 J/(kg·K) |
| 2 Btu_IT/(lbm·°F) | 8373.6 J/(kg·K) |
| 3 Btu_IT/(lbm·°F) | 12560.4 J/(kg·K) |
| 4 Btu_IT/(lbm·°F) | 16747.2 J/(kg·K) |
| 5 Btu_IT/(lbm·°F) | 20934 J/(kg·K) |
| 6 Btu_IT/(lbm·°F) | 25120.8 J/(kg·K) |
| 7 Btu_IT/(lbm·°F) | 29307.6 J/(kg·K) |
| 8 Btu_IT/(lbm·°F) | 33494.4 J/(kg·K) |
| 9 Btu_IT/(lbm·°F) | 37681.2 J/(kg·K) |
| 10 Btu_IT/(lbm·°F) | 41868 J/(kg·K) |
| 15 Btu_IT/(lbm·°F) | 62802 J/(kg·K) |
| 20 Btu_IT/(lbm·°F) | 83736 J/(kg·K) |
| 25 Btu_IT/(lbm·°F) | 104670 J/(kg·K) |
| 30 Btu_IT/(lbm·°F) | 125604 J/(kg·K) |
| 40 Btu_IT/(lbm·°F) | 167472 J/(kg·K) |
| 50 Btu_IT/(lbm·°F) | 209340 J/(kg·K) |
| 75 Btu_IT/(lbm·°F) | 314010 J/(kg·K) |
| 100 Btu_IT/(lbm·°F) | 418680 J/(kg·K) |
Joule per Kilogram Kelvin (J/(kg·K))
The SI unit of specific heat capacity (c), representing the heat energy in joules required to raise 1 kilogram of a substance by 1 kelvin.
IT BTU per Pound Mass Degree Fahrenheit (Btu_IT/(lbm·°F))
The US customary specific heat capacity unit, defined as 1 IT BTU per pound-mass per °F interval. It is numerically equal to exactly 4,186.8 J/(kg·K).
🔗
Related Conversion Calculators
IT BTU per Pound Mass Degree Fahrenheit to Joule per Kilogram Kelvin→Joule per Kilogram Kelvin to Kilojoule per Kilogram Kelvin→Kilojoule per Kilogram Kelvin to Joule per Kilogram Kelvin→IT Calorie per Gram Degree Celsius to Joule per Kilogram Kelvin→Thermochemical Calorie per Gram Degree Celsius to Joule per Kilogram Kelvin→